3.如【圖 15】所示之電路,
、R1= 1 Ω、R2= 6 Ω、R3= 8 Ω、XL1= 8 Ω、XL2= 5 Ω、XC= 6 Ω,試求:(15 分)
遇到困難了!
(+)//(+)我也會,但拆開就不行了

RX串聯轉並聯:R並=(R串2+X串2)/R串,X並=(R串2+X串2)/X並
=> R2'=(R22+XL12)/R2=(62+82)/6=100/6,
XL1'=100/j8;
R3'=[82+(-6)2]/8=100/8
XC'=[82+(-6)2]/(-6)=-100/j6
=> (1/R2')+(1/XL1')+(1/R3')+(1/XC')
=(6+j8+8-j6)/100
=(14+j2)/100
=(7+j)/50
所求=[50/(7+j)]+1+j5
={[50*(7-j)]/[(7+j)(7-j)]}+1+j5
=(7-j)+1+j5
=8+j4
10<37