11 如圖所示電路,Ao = 105 ,求此電路之閉迴路電壓增益約為何?
(A)1
(B)100
(C)1000
(D)100000
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統計: A(121), B(9), C(1), D(38), E(0) #1719220
統計: A(121), B(9), C(1), D(38), E(0) #1719220
詳解 (共 3 筆)
#5280716
Ao * (Vin - Vo) = Vo
Ao *Vin = (1+Ao) Vo
Vo/Vin = Ao / (1+Ao)
Ao = 105>>1 Ao / (1+Ao) 大約=1
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#3641307
回授因子beta=Vf/Vo=1
閉迴路增益Af=Ao/(1+Ao*beta)=Ao/(1+Ao)
Ao >>1 ,故Af=Ao/Ao=1
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