4. 求5fcef1e193185.jpg=           。

詳解 (共 2 筆)

vivahome.jo
vivahome.jo
詳解 #4567626
2021/02/28

[1+1/(2-1)(2+1)][1+1/(3-1)(3+1)]...[1+1/(111-1)(111+1)]

=[22/(22-1)][32/(32-1)]...[1112/(1112-1)]

=(2x3x...x111)2/ (2-1)(3-1)...(111-1)(2+1)(3+1)...(111+1)

=(2x3x...x111)2/ (1x2x3x...x110)(3x4x...x112)

=(2x3x...x111)2 / (2x111x112)(3x4x...x110)2,

=(2x111)2 / (2x111x112)

=(2x111)/112

=111/56

mark123
mark123
詳解 #4431502
2020/12/12
先看通式 (1+ [1/(n-1)(n...
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